Answer:
B. 468
Step-by-step explanation:
We have
[tex]a_1=156,\ r=\dfrac{2}{3}[/tex]
If |r| < 1, then the formula of a sum of an infinite geometric sequence is:
[tex]S=\dfrac{a_1}{1-r}[/tex]
Substitute:
[tex]S=\dfrac{156}{1-\frac{2}{3}}=\dfrac{156}{\frac{1}{3}}=156\cdot\dfrac{3}{1}=468[/tex]
