Answer:
[tex]\large\boxed{9-3\dfrac{7}{8}=5\dfrac{1}{8}}[/tex]
Step-by-step explanation:
METHOD #1:
[tex]9-3\dfrac{7}{8}[/tex]
Convert 9 the fraction with denominator of 8 and convert the mixed number to the improper fraction:
[tex]\dfrac{9\cdot8}{8}-\dfrac{3\cdot8+7}{8}=\dfrac{72}{8}-\dfrac{31}{8}=\dfrac{41}{8}=\dfrac{40+1}{8}=\dfrac{40}{8}+\dfrac{1}{8}=5\dfrac{1}{8}[/tex]
METHOD #2:
[tex]9-3\dfrac{7}{8}=9-3-\dfrac{7}{8}=6-\dfrac{7}{8}=5+1-\dfrac{7}{8}=5+\dfrac{8}{8}-\dfrac{7}{8}=5\dfrac{1}{8}[/tex]
