Answer:
[tex]x^2 + y^2 -4x -6y + 9 = 0[/tex]
Step-by-step explanation:
To write a circle in standard form, expand the equation of the circle and move all terms to one side.
[tex](x-2)^2 + (y-3)^2 = 4\\x^2 -4x + 4 + y^2 -6y + 9 = 4\\x^2 +y^2 - 4x - 6y + 13 = 4\\x^2 + y^2 -4x -6y + 9 = 0[/tex]
