antonyjoshua18
antonyjoshua18 antonyjoshua18
  • 16-03-2019
  • Mathematics
contestada

Factor 6u^2·(2u−5)^2−12u^2·(2u−5)·(u+5)

Respuesta :

Аноним Аноним
  • 16-03-2019

Start with

[tex]6u^2(2u-5)^2-12u^2(2u-5)(u+5)[/tex]

We can factor a 6 from both terms:

[tex]6\big(u^2(2u-5)^2-2u^2(2u-5)(u+5)\big)[/tex]

We can also factor [tex] u^2 [/tex]

[tex]6u^2\big((2u-5)^2-2(2u-5)(u+5)\big)[/tex]

Finally, both terms inside the parenthesis contain a factor of [tex] 2u-5 [/tex]

[tex]6u^2(2u-5)\big((2u-5)-2(u+5)\big)[/tex]

Finally, we can simplify the terms inside the parenthesis:

[tex]6u^2(2u-5)\big(2u-5-2u-10\big) = 6u^2(2u-5)\big(-15) = -90u^2(2u-5)[/tex]

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