Answer:
TRUE
Step-by-step explanation:
[tex]\text{The quadratic equation:}[/tex]
[tex]ax^2+bx+c=0[/tex]
[tex]\text{The discriminant:}[/tex]
[tex]b^2-4ac[/tex]
[tex]\text{If}\ b^2-4ac<0\ \text{then the equation has no solution}\\\\\text{If}\ b^2-4ac=0\ \text{then the equation has one solution}\ x=\dfrac{-b}{2a}\\\\\text{If}\ b^2-4ac>0\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}[/tex]
