Answer:
[tex]\large\boxed{x=\pm\dfrac{5}{2}}[/tex]
Step-by-step explanation:
[tex]4x^2-25=0\qquad\text{add 25 to both sides}\\\\4x^2=25\qquad\text{divide both sides by 4}\\\\x^2=\dfrac{25}{4}\to x=\pm\sqrt{\dfrac{25}{4}}\\\\x=\pm\dfrac{\sqrt{25}}{\sqrt4}\\\\x=-\dfrac{5}{2}\ \vee\ x=\dfrac{5}{2}[/tex]
