Answer:
-6
Step-by-step explanation:
[tex]Use\\\\(a^n)^m=a^{nm}\\\\\dfrac{a^n}{a^m}=a^{n-m}\\------------------\\\\\dfrac{(x^{25})^{-6}}{(x^{-3})^{48}}=\dfrac{x^{(25)(-6)}}{x^{(-3)(48)}}=\dfrac{x^{-150}}{x^{-144}}=x^{-150-(-144)}=x^{-150+144}=x^{-6}[/tex]
