Answer:
[tex]\bar {AQ} =\bar {QB}[/tex]
Step-by-step explanation:
Since line L passes through the center of the circle and it is perpendicular to chord AB, it bisects chord AB.
This means that L is the locus of points equidistant from A and B.
This also means that Q is the midpoint of AB.
Hence the correct answer is [tex]\bar {AQ} =\bar {QB}[/tex]
