Answer:
[tex]\frac{3(6)-1}{2(6)+1}[/tex]
Step-by-step explanation:
we have
[tex]r(x)=3x-1[/tex]
[tex]s(x)=2x+1[/tex]
so
[tex]\frac{r}{s}(x)=\frac{r(x)}{s(x)}=\frac{3x-1}{2x+1}[/tex]
substitute the value of [tex]x=6[/tex] in the expression
[tex]\frac{r}{s}(6)=\frac{3(6)-1}{2(6)+1}=\frac{17}{13}[/tex]
