Answer:
[tex]\large\boxed{(x-9)(x^2-3x-2)=x^3-12x^2+25x+18}[/tex]
Step-by-step explanation:
Use FOIL: (a + b)(c + d) = ac + ad + bc + bd
[tex](x-9)(x^2-3x-2)\\\\=(x)(x^2)+(x)(-3x)+(x)(-2)+(-9)(x^2)+(-9)(-3x)+(-9)(-2)\\\\=x^3-3x^2-2x-9x^2+27x+18\\\\\text{combine like terms}\\\\=x^3+(-3x^2-9x^2)+(-2x+27x)+18\\\\=x^3-12x^2+25x+18[/tex]
