Answer:
D
Step-by-step explanation:
Using the trigonometric identity
• csc²Θ = 1 + cot²Θ ( cotΘ = [tex]\frac{4}{3}[/tex]), hence
csc²Θ = 1 + ([tex]\frac{4}{3}[/tex])²
= 1 + [tex]\frac{16}{9}[/tex] = [tex]\frac{25}{9}[/tex]
Take the square root of both sides
cscΘ = [tex]\sqrt{\frac{25}{9} }[/tex] = [tex]\frac{5}{3}[/tex] → D
