Answer:
vertical asymptote at x=2 and x=-1
Step-by-step explanation:
[tex]y= \frac{x^2-5x}{x^2-x-2}[/tex]
To find out vertical asymptote we set the denominator =0 and solve for x
[tex]x^2 - x - 2=0[/tex]
now factor left hand side
find out two factors whose product is -2 and sum is -1
-2 times 1 = -2
-2+1 = -1
(x-2)(x+1) =0
x-2 =0 so x= 2
x+1 =0 so x=-1
vertical asymptote at x=2 and x=-1
