Answer:
OPtion I is right
Step-by-step explanation:
Once we know sin of an angle, and it lies in II quadrant, we know that
cos, sec, tan and cot would be negative but csc will be positive.
So use the fact that
[tex]sin^{2}t+cos^{2} t=1\\cost =-\sqrt{1-sin^2 t}[/tex]
Thus cos is obtained using negative square root.
Now tan = sin/cos, and sec = 1/cos:
cot =1/tan and csc =1/sin
Thus all value can be obtained easily
So option I
