First we must convert the mixed numbers to the improper fractions:
[tex]2\dfrac{1}{3}=\dfrac{2\cdot3+1}{2}=\dfrac{7}{3}\\\\5\dfrac{1}{3}=\dfrac{5\cdot3+1}{3}=\dfrac{16}{3}[/tex]
[tex]2\dfrac{1}{3}\cdot5\dfrac{1}{3}=\dfrac{7}{3}\cdot\dfrac{16}{3}=\dfrac{7\cdot16}{3\cdot3}=\dfrac{112}{9}=\dfrac{108+4}{9}=12\dfrac{4}{9}\\\\Answer:\ \boxed{2\dfrac{1}{3}\cdot5\dfrac{1}{3}=12\dfrac{4}{9}}[/tex]
