Answer:
(3x+2) ^2
x = -2/3
Step-by-step explanation:
9x^2+12x+4 = 0
We need to recognize that this is perfect squares
(a + b)2 = a^2 + 2ab + b^2;
Where a = 3x and b =2
a^2 = 9x^2 2ab = 2*3x*2 = 12x and b^2 = 2^2 =4
So we can factor this as (3x+2) ^2
If you want to solve
We can use the zero product property
(3x+2) ^2 =0
Take the square root of each side
3x+2 =0
Subtract 2 from each side
3x=-2
Divide by 3
3x/3 = -2/3
