Answer:
1
Step-by-step explanation:
given [tex]\frac{2x+2y-1}{2y+1}[/tex]
To evaluate substitute x = 1, y = 1 into the expression
= [tex]\frac{2(1)+2(1)-1}{2(1)+1}[/tex]
= [tex]\frac{2+2-1}{2+1}[/tex]
= [tex]\frac{3}{3}[/tex] = 1
