Rewrite it in the form; a^2 + 2ab + b^2, where a = 3x and b = 8
(3x)^2 + 2(3x)(8) + 8^2
Use the Square of Sum: (a + b)^2 = a^2 + 2ab + b^2
(3x + 8)^2
[tex]9x^2+48x+64=3^2x^2+2(3x)(8)+8^2=(3x)^2+2(3x)(8)+8^2\\\\\text{Use}\ (a+b)^2=a^2+2ab+b^2\\\\=\boxed{(3x+8)^2=(3x+8)(3x+8)}\\\\\text{Other method:}\\\\9x^2+48x+64=9x^2+24x+24x+64=3x(3x+8)+8(3x+8)\\\\=\boxed{(3x+8)(3x+8)}[/tex]
