Answer: The answer is AB =10
Step-by-step explanation:
In the given figure there is a rectangle PQRS
Given :PQ=12
PS=16
Since it is a rectangle
∵ PQ=RS
and PS=QR
i.e. QR=16
A is mid point of PQ
⇒QA =[tex]\frac{12}{2}[/tex]
=6
B is mid point of QR
⇒ QB=[tex]\frac{16}{2}[/tex]
=8
So In Δ AQB
Applying pythagoras theorem
AQ² +BQ² =AB²
∵ AB²=6²+8²
=36 +64
=100
i.e. AB=√100
=10
