[tex]r=\left(\dfrac{F}{P}\right)^\frac{1}{n}-1\\\\\text{We have}\\\\n=10\\\\F=3.53\\\\P=1.46\\\\\text{Substitute:}\\\\r=\left(\dfrac{3.53}{1.46}\right)^\frac{1}{10}-1=\sqrt[10]{\dfrac{3.53}{1.46}}-1\approx1.0923-1=0.0923\\\\0.0923=0.0923\cdot100\%=9.23\%=\boxed{9.2\%}[/tex]
