Put the vales of x and y to the expression:
[tex]x=-1;\ y=3\\\\\dfrac{5x^{-6}y^{-2}}{y}=\dfrac{5(-1)^{-6}(3)^{-2}}{3}=\dfrac{5(-1)^6\left(\dfrac{1}{3}\right)^2}{3}=\dfrac{5(1)\left(\dfrac{1}{9}\right)}{3}=\dfrac{\dfrac{5}{9}}{3}\\\\=\dfrac{5}{9}\cdot\dfrac{1}{3}=\boxed{\dfrac{5}{27}}[/tex]
