Ashh586 Ashh586
  • 20-12-2018
  • Mathematics
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Solve for x. The polygons are similar

Solve for x The polygons are similar class=

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Аноним Аноним
  • 20-12-2018

[tex]\frac{8x-2}{42}=\frac{63}{49}\\\frac{8x-2}{42}=\frac{9}{7}\\7(8x-2)=9\cdot42\ /:7\\8x-2=9\cdot6\\8x-2=54\\8x=54+2\\8x=56\ /:8\\x=7[/tex]

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