[tex]12x+4>16\qquad\text{subtract 4 from both sides}\\\\12x>12\qquad\text{divide both sides by 12}\\\\\boxed{x>1}\\\\or\\\\3x-5<-14\qquad\text{add 5 to both sides}\\\\3x<-9\qquad\text{divide both sides by 3}\\\\\boxed{x<-3}\\\\Answer:\ \boxed{x<-3\ or\ x>1}[/tex]
