Answer:
A
Step-by-step explanation:
given y = 3(x + 2)(x - 2) = 3(x² - 4) = 3x² - 12
for the y- intercept let x = 0
f(0) = - 12 → y-intercept is the point (0, - 12) → True
for x-intercepts let y = 0
3(x + 2)(x - 2) = 0
x + 2 = 0 ⇒ x = - 2
x - 2 = 0 ⇒ x = 2
x- intercepts are (- 2, 0) and (2, 0) → not (0, - 12)
since f(x) = 3x² - 12 is symmetric about the y-axis
the vertex is at (0, - 12 ) → not (- 2, 2)
