hamptoncalcalese
hamptoncalcalese hamptoncalcalese
  • 19-12-2018
  • Mathematics
contestada

what two consecutive numbers that square root of 101 lies between

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gmany
gmany gmany
  • 31-12-2018

[tex]10<\sqrt{101}<11\\\\because\\\\10^2=100\\(\sqrt{101})^2=101\\11^2=121\\\\10^2=100<(\sqrt{101})^2=101<11^2=121[/tex]

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