dominicphillips00 dominicphillips00

17-12-2018
Mathematics

contestada

What is the remainder when the polynomial f(x)=3x^3-4x^2+2x+8 is divided by (x-5)

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jimrgrant1 jimrgrant1

17-12-2018

Answer:

remainder = 290

Step-by-step explanation:

[tex]\frac{3x^3-4x^2+2x+8}{x-5}[/tex]

= 3x² + 11x + 57 + [tex]\frac{290}{x-5}[/tex]

quotient = 3x² + 11x + 57 and remainder = 290

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