[tex]\dfrac{(x^5yz^4)^3}{x^3yz}=x^ay^bz^c\\\\\text{Use}\ (a^n)^m=a^{nm}\ \text{and}\ \dfrac{a^n}{a^m}=a^{n-m}\\\\\dfrac{(x^5)^3(y)^3(z^4)^3}{x^3yz}=\dfrac{x^{15}y^3z^{12}}{x^3yz}=x^{15-3}y^{3-1}z^{12-1}=x^{12}y^2z^{11}\\\\Answer:\ a=12,\ b=2,\ c=11[/tex]
