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  • 17-11-2018
  • Mathematics
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Whats the answer?
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gmany
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  • 18-11-2018

[tex]\dfrac{4bc}{16b}=\dfrac{4}{16}\cdot\dfrac{bc}{b}=\dfrac{1}{4}\cdot c=\boxed{\dfrac{c}{4}}[/tex]

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