Answer:
I=[tex]\int\limits {sin^5\theta\ \, d\theta[/tex]
Step-by-step explanation:
substitute x=sinθ
dx=cosθdθ
the integrand becomes sin^5θcosθdθ / sqrt(1 - sin^2θ)
1-sin^2θ=cos^2θ
sqrt(1-sin^2θ)=cosθ
substitute back into the integrand
sin^5θcosθdθ/cosθ
=sin^5θdθ
ans is 5.
