minor axis is shorter than major axist.
The equation of a ellipse:
[tex]\dfrac{(x-h)^2}{a}+\dfrac{(y-k)^2}{b}=1[/tex]
(h, k) - center
a, b - minor or major axis (a-horizontal, b-vertical)
The minor axis is horizontal, therefore a is minor axis and b is major axis.
Therefore your answer is:
[tex]\dfrac{(x-2)^2}{10}+\dfrac{(y-3)^2}{12}=1[/tex]
