Respuesta :

mathstudent55

Answer:

[tex] \sqrt{2 + 1} < \sqrt{2 + 2} [/tex]

Step-by-step explanation:

[tex] \sqrt{2 + 1} = \sqrt{3} = 1.73205... [/tex]

[tex] \sqrt{2 + 2} = \sqrt{4} = 2 [/tex]

Since [tex] 1.73205... < 2 [/tex], then

[tex] \sqrt{2 + 1} < \sqrt{2 + 2} [/tex]