Look at the attached picture:
First we solve for the bigger triangle:
8 = 2x
x = [tex]\frac{8}{2}[/tex]
Smallest side: x = 4
Longest side: x[tex]\sqrt{3}[/tex] = 4[tex]\sqrt{3}[/tex]
Now for the smaller triangle:
Since the longest side in the smaller triangle is 4 = y[tex]\sqrt{3}[/tex] ,
then y = [tex]\frac{4\sqrt{3} } {3}[/tex]
