Answer:
Step-by-step explanation:
a. AB pass thro' (0,3) n (5,0)
so its eqn is (y-3)/(x-0) = (3-0)/(0-5)=-3/5
y=(-3/5)x + 3
b. area of ABC=1/2*base*height
=1/2*3*5=7.5
c. line perpendicular to AB has slope = 1/slope of line AB
= 1/(-3/5)
= -5/3
it passes thro' A (0,3) which is the y-intercept
so its eqn is y = (-5/3)x + 3
