johnsonkav2002 johnsonkav2002
  • 16-10-2018
  • Mathematics
contestada

∠DHG= 4x+12 and ∠BGH=8x-24. Find the measure of ∠DHG

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belgrad belgrad
  • 30-10-2018

by property of parallel lines (lines DH and BG are parallel):

∠DHG = 180° - ∠BGH  [∵ corresponding angles are equal]

⇒ 4x + 12 = 180 - (8x - 24)

⇒ 12x -12 = 180

⇒ 12x = 192

∴ x = 16

now substituting this value of x in ∠DHG:

4 × 16 + 12 = 76°


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