Hi, to know the x-int you have to solve for x for
[tex]first \: step \\ y = \frac{1}{2} x + 2 \\ subtract \: two \: on \: both \: sides \\ y - 2 = \frac{1}{2} x + 2 - 2 \\ you \: end \: with \\ y - 2 = \frac{1}{2} x \\[/tex]
[tex]now \: you \: multiply \: by \: the \: recipical \\ (y - 2)( \frac{2}{1} ) = \frac{1}{2} x\times \frac{2}{1} \\ your \: solution \: is \\ 2y - 4 = x \: [/tex]
