y = - 4x + 1 → C
the equation of the line in ' slope-intercept form ' is
y = mx + c ( m is the slope and c the y-intercept )
from the graph c = 1
using the points ( 0 , 1 ) and (1 , - 3 )
m = (- 3 - 1 )/( 1 - 0) = (- 4 )/1 = -4
equation is y = - 4x + 1
