Respuesta :

s1m1
X^2 +3x-4=0
(X+4)(x-1)=0 so x = -4 and x=1 are solutions
tramserran

x² + 3x - 4 = 0 →  (-4 = -1 * 4 or -2 * 2)  →  -1 + 4 = 3 and -2 + 2 = 0

(x - 1) (x + 4) = 0

x - 1 = 0       x + 4 = 0

  +1   +1        -4     -4

   x = 1              x = -4  

Answer: 1, -4

           

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