[tex]-3\dfrac{1}{4}+\left(-1\dfrac{3}{4}\right)=-\left(3\dfrac{1}{4}+1\dfrac{3}{4}\right)\\\\=-\left[(3+1)+\left(\dfrac{1}{4}+\dfrac{3}{4}\right)\right]\\\\=-\left(4+\dfrac{1+3}{4}\right)\\\\=-\left(4+\dfrac{4}{4}\right)\\\\=-(4+1)\\\\=-5[/tex]
