Respuesta :

mathstudent55

−4(z + 3) − 4(5 − 4z) =

= -4z - 12 - 20 + 16z

= 12z - 32

gmany

[tex]-4(z+3)-4(5-4z)\\\\\text{use distributive property}\\\\=(-4)(z)+(-4)(3)+(-4)(5)+(-4)(-4z)\\\\=-4z-12-20+16z\\\\=(-4z+16z)+(-12-20)\\\\=\boxed{12z-32}[/tex]

Otras preguntas