A particle moves along the x axis. Its position as function of time is given by x=6.8t+8.5t^2, where t is in seconds and x is in meters. What is the acceleration as a function of time?
displacement=x-0=x (assuming the journey started at t=0) time=t x=ut+1/2 at^2 u=initial velocity=0 acceleration=a=((x-ut)*2)/t^2 a=(13.6t+17t^2)/t^2 a=17+13.6/t
