Respuesta :

gmany

Paul is incorrect.

[tex] 3\dfrac{1}{5}\times2\dfrac{3}{8}=\dfrac{3\cdot5+1}{5}\times\dfrac{2\cdot8+3}{8}=\dfrac{16}{5}\times\dfrac{19}{8}=\dfrac{2}{5}\times\dfrac{19}{1}\\\\=\dfrac{38}{5}=7\dfrac{3}{5}\neq6\dfrac{3}{40} [/tex]

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