lizzyhernandez lizzyhernandez
  • 19-08-2018
  • Mathematics
contestada

8x^-9+(-3x^-3y-2)(5/x^6y-2)

8x93x3y25x6y2 class=

Respuesta :

Lazerpent
Lazerpent Lazerpent
  • 19-08-2018

[tex] 8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}}) [/tex]

the first step is to deal with the negative exponents, which causes numbers to go to the other side of the fraction

8x^{-9}+(-3x^{-3}y^{-2})(\frac{5}{x^6y^{-2}})

goes to

[tex] \frac{8}{x^9}+(\frac{-3}{x^3y^2})(\frac{5y^2}{x^6}) [/tex]

now we can simplify the multiplied terms

[tex] \frac{8}{x^9}+(\frac{-15}{x^9}) [/tex]

Now that we have common bases, we can add the 2 fractions together to get

[tex] \frac{-7}{x^9} [/tex]

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