Respuesta :

DeanR

Unrecursively, that's

[tex]f(n) = (2n)^2 = 4n^2[/tex]

A quadratic will have a linear first difference:

[tex]f(n+1) - f(n) = 4(n+1)^2 - 4n^2 = 4n^2 + 8n + 4 - 4n^2 = 8n+ 4[/tex]

So we get

f(1) = 4

f(n+1) = f(n) + 8n + 4


Otras preguntas