Hi!
First, let's solve for d.
To get [tex] 18y^{6} [/tex], you need to add ³ + ³. So d has to equal ³.
[tex] (cy^3)(9y^3) = 18y^{6} [/tex]
Now solve for c.
Because 9 * 2 = 18, c has to equal 2.
[tex] (2y^3)(9y^3) = 18y^{6} [/tex]
The answer is
c = 2
d = 3
Hope this helps! :)
-Peredhel
