edgarlopez56881 edgarlopez56881
  • 20-07-2018
  • Chemistry
contestada

Given that e = 9.0 v , r = 98 ω and c = 23 μf , how much charge is on the capacitor at time t = 4.0 ms

Respuesta :

ralphwx1 ralphwx1
  • 20-07-2018
Let charge across the capacitor be Q, current through the circuit be I.
Voltage difference across the resistor = rI
Voltage difference across the capacitor = Q/c
Loop rule: net voltage change through a loop must be zero, so
9 = rI + Q/c. Since I = dQ/dt,
r dQ/dt + Q/c = 9
Solving, Q = 9c (1 - e^(t/rc)). Plug in the numbers from the problem for the numerical answer.
Answer Link

Otras preguntas

Can anybody help me with this please
screw it.. helps me pleaseee all the questions -_-
What the answer too question two now now
Alonzo has completed 44 Deliveries so far this week he needs to make 55 deliveries for the week what percentage of his delivery has Alonzo completed?80%
A character’s viewpoint is the way a character thinks about things. the reason a character acts in a certain way. the influences that come from outside a charac
Why do you think the queen changed from being angry and threatening to sympathetic? Cite evidence to support your claim.
Points for 2-3 people <3
In triangle ABC, one angle measures 68°, another measures 19°, what is the measure of the third angle? *
The net of a square pyramid is shown in the diagram. What is the total surface area of the square pyramid in square inches?
Lauren had 2 2/3 yards of ribbon. She used 4/5 of the ribbon. How many yards of ribbon did Lauren use?