Answer
[tex]\boxed {d= \frac{19}{3}}[/tex]
Solution
Simplify both sides of the equation.
[tex] \frac{7}{3} + \frac{-7}{3} [/tex]
We are left with d = 4+[tex] \frac{7}{3} [/tex]
Add
[tex] \frac{12}{3}+\frac{7}{3} =\frac{19}{3} [/tex]
Hence, d = [tex] \frac{19}{3} [/tex]
