Respuesta :

we are given

[tex] \frac{(3x^2)^4y^2x^{-2}}{(x^{-3}y^5)} [/tex]

[tex] \frac{3^4x^8y^2x^{-2}}{x^{-3}y^5} [/tex]

we can make exponent positive

[tex] =\frac{3^4x^8y^2x^{-2}*x^3}{y^5} [/tex]

[tex] =81x^{9}y^{-3} [/tex]..............Answer

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