For this, since 4y - 7 and 2y - 1 are congruent, we can solve for y by setting them equal to each other.
[tex] 4y-7=2y-1 [/tex]
Firstly, subtract 2y on both sides of the equation. [tex] 2y-7=-1 [/tex]
Next, add 7 on both sides of the equation. [tex] 2y=6 [/tex]
Finally, divide 2 on both sides of the equation, and your answer will be y = 3
