x² - x - 12 = 0
[tex] x = \dfrac{-b \pm \sqrt{b^{2} - 4ac}}{2a} [/tex]
[tex] x = \dfrac{1 \pm \sqrt{(-1)^{2} - 4(1)(-12)}}{2(1)} [/tex]
x = 4 or -3
Answer: 4 or -3
