Respuesta :

[tex]\bf \textit{arc's length}\\\\ s=r\theta ~~ \begin{cases} r=radius\\ \theta =angle~in\\ \qquad radians\\ ------\\ r=24\\ \theta =\frac{5\pi }{6} \end{cases}\implies s=24\cdot \cfrac{5\pi }{6}\implies s=20\pi [/tex]

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