n = # of nickels
d = # of dimes
d + n = 52 so d = 52 - n
0.10d + 0.05n = 3.55
substitute d = 52 - n into 0.10d + 0.05n = 3.55
0.10d + 0.05n = 3.55
0.10(52 - n) + 0.05n = 3.55
5.2 - 0.10n + 0.05n = 3.55
-0.05n = - 1.65
n = 33 nickels
d = 52 - 33
d = 19 dimes
Answer:
There are 33 nickels and 19 dimes.
